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20001021000113 is a prime number
BaseRepresentation
bin1001000110000110110011…
…10000000111100110110001
32121211002010112122200111202
410203003121300013212301
510110144042334000423
6110312201525420545
74133011642255406
oct443033160074661
977732115580452
1020001021000113
116411426a2458a
1222b03b956a755
13b2111b99460a
144d20a9ab42ad
1524a414814728
hex1230d9c079b1

20001021000113 has 2 divisors, whose sum is σ = 20001021000114. Its totient is φ = 20001021000112.

The previous prime is 20001021000101. The next prime is 20001021000119. The reversal of 20001021000113 is 31100012010002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14517799309729 + 5483221690384 = 3810223^2 + 2341628^2 .

It is a cyclic number.

It is not a de Polignac number, because 20001021000113 - 28 = 20001020999857 is a prime.

It is a super-2 number, since 2×200010210001132 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20001021000094 and 20001021000103.

It is not a weakly prime, because it can be changed into another prime (20001021000119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000510500056 + 10000510500057.

It is an arithmetic number, because the mean of its divisors is an integer number (10000510500057).

Almost surely, 220001021000113 is an apocalyptic number.

It is an amenable number.

20001021000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20001021000113 is an equidigital number, since it uses as much as digits as its factorization.

20001021000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 20001021000113 its reverse (31100012010002), we get a palindrome (51101033010115).

The spelling of 20001021000113 in words is "twenty trillion, one billion, twenty-one million, one hundred thirteen", and thus it is an aban number.