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2000112013 = 4243471391
BaseRepresentation
bin111011100110111…
…0100100110001101
312011101120012212201
41313031310212031
513044012041023
6530245201501
7100364446234
oct16715644615
95141505781
102000112013
11937013839
12479a00291
1325b4b6343
1414d8c7b1b
15ba8d5bad
hex7737498d

2000112013 has 4 divisors (see below), whose sum is σ = 2000587648. Its totient is φ = 1999636380.

The previous prime is 2000112011. The next prime is 2000112077. The reversal of 2000112013 is 3102110002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2000112013 - 21 = 2000112011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000112011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231453 + ... + 239938.

It is an arithmetic number, because the mean of its divisors is an integer number (500146912).

Almost surely, 22000112013 is an apocalyptic number.

It is an amenable number.

2000112013 is a deficient number, since it is larger than the sum of its proper divisors (475635).

2000112013 is an equidigital number, since it uses as much as digits as its factorization.

2000112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 475634.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 2000112013 is about 44722.6118758733. The cubic root of 2000112013 is about 1259.9445707119.

Adding to 2000112013 its reverse (3102110002), we get a palindrome (5102222015).

The spelling of 2000112013 in words is "two billion, one hundred twelve thousand, thirteen".

Divisors: 1 4243 471391 2000112013