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200011202103 = 366670400701
BaseRepresentation
bin1011101001000110011…
…0001011111000110111
3201010021010100210220010
42322101212023320313
511234110331431403
6231514530111303
720310315111126
oct2722146137067
9633233323803
10200011202103
1177908122539
123291b41b533
1315b26741c3b
149975799abd
155309438603
hex2e9198be37

200011202103 has 4 divisors (see below), whose sum is σ = 266681602808. Its totient is φ = 133340801400.

The previous prime is 200011202063. The next prime is 200011202117. The reversal of 200011202103 is 301202110002.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 200011202103 - 28 = 200011201847 is a prime.

It is a super-2 number, since 2×2000112021032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200011206103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33335200348 + ... + 33335200353.

It is an arithmetic number, because the mean of its divisors is an integer number (66670400702).

Almost surely, 2200011202103 is an apocalyptic number.

200011202103 is a deficient number, since it is larger than the sum of its proper divisors (66670400705).

200011202103 is an equidigital number, since it uses as much as digits as its factorization.

200011202103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66670400704.

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 200011202103 its reverse (301202110002), we get a palindrome (501213312105).

The spelling of 200011202103 in words is "two hundred billion, eleven million, two hundred two thousand, one hundred three".

Divisors: 1 3 66670400701 200011202103