Base | Representation |
---|---|
bin | 1001000110000111001010… |
… | …01000101110011101100001 |
3 | 2121211002121212001111020020 |
4 | 10203003211020232131201 |
5 | 10110144440233000342 |
6 | 110312232511304053 |
7 | 4133016451606566 |
oct | 443034510563541 |
9 | 77732555044206 |
10 | 20001212000097 |
11 | 641151481a709 |
12 | 22b045151b029 |
13 | b2114c41a263 |
14 | 4d20c71d286d |
15 | 24a4264920ec |
hex | 1230e522e761 |
20001212000097 has 16 divisors (see below), whose sum is σ = 26718956732160. Its totient is φ = 13308824816000.
The previous prime is 20001212000089. The next prime is 20001212000101. The reversal of 20001212000097 is 79000021210002.
It is a cyclic number.
It is not a de Polignac number, because 20001212000097 - 23 = 20001212000089 is a prime.
It is a super-3 number, since 3×200012120000973 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (20001212000017) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1338472 + ... + 6464822.
It is an arithmetic number, because the mean of its divisors is an integer number (1669934795760).
Almost surely, 220001212000097 is an apocalyptic number.
It is an amenable number.
20001212000097 is a deficient number, since it is larger than the sum of its proper divisors (6717744732063).
20001212000097 is a wasteful number, since it uses less digits than its factorization.
20001212000097 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5128824.
The product of its (nonzero) digits is 504, while the sum is 24.
Adding to 20001212000097 its reverse (79000021210002), we get a palindrome (99001233210099).
The spelling of 20001212000097 in words is "twenty trillion, one billion, two hundred twelve million, ninety-seven", and thus it is an aban number.
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