Base | Representation |
---|---|
bin | 1001000110000111001011… |
… | …01111010001010101110001 |
3 | 2121211002122120001211202220 |
4 | 10203003211233101111301 |
5 | 10110200000324320213 |
6 | 110312233512031253 |
7 | 4133016633522363 |
oct | 443034557212561 |
9 | 77732576054686 |
10 | 20001222104433 |
11 | 641151a4a11a9 |
12 | 22b0454992529 |
13 | b2115154745b |
14 | 4d20c86a2d33 |
15 | 24a4272dae23 |
hex | 1230e5bd1571 |
20001222104433 has 8 divisors (see below), whose sum is σ = 26672509831200. Its totient is φ = 13332041223648.
The previous prime is 20001222104411. The next prime is 20001222104447. The reversal of 20001222104433 is 33440122210002.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20001222104433 - 212 = 20001222100337 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20001222104933) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 526689343 + ... + 526727316.
It is an arithmetic number, because the mean of its divisors is an integer number (3334063728900).
Almost surely, 220001222104433 is an apocalyptic number.
It is an amenable number.
20001222104433 is a deficient number, since it is larger than the sum of its proper divisors (6671287726767).
20001222104433 is a wasteful number, since it uses less digits than its factorization.
20001222104433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1053422991.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 20001222104433 its reverse (33440122210002), we get a palindrome (53441344314435).
The spelling of 20001222104433 in words is "twenty trillion, one billion, two hundred twenty-two million, one hundred four thousand, four hundred thirty-three".
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