2000134103333 has 4 divisors (see below), whose sum is σ = 2000137273920. Its totient is φ = 2000130932748.

The previous prime is 2000134103281. The next prime is 2000134103371. The reversal of 2000134103333 is 3333014310002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2000134103333 - 2³⁰ = 1999060361509 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2000134103299 and 2000134103308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000134103393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 281735 + ... + 2019812.

It is an arithmetic number, because the mean of its divisors is an integer number (500034318480).

Almost surely, 2^{2000134103333} is an apocalyptic number.

It is an amenable number.

2000134103333 is a deficient number, since it is larger than the sum of its proper divisors (3170587).

2000134103333 is an equidigital number, since it uses as much as digits as its factorization.

2000134103333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3170586.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 2000134103333 its reverse (3333014310002), we get a palindrome (5333148413335).

The spelling of 2000134103333 in words is "two trillion, one hundred thirty-four million, one hundred three thousand, three hundred thirty-three".