Base | Representation |
---|---|
bin | 11101000110110001010… |
… | …010000110000101001011 |
3 | 21002012200210012000012121 |
4 | 131012301102012011023 |
5 | 230232233312301441 |
6 | 4130503211152111 |
7 | 264335121236005 |
oct | 35066122060513 |
9 | 7065623160177 |
10 | 2000134103371 |
11 | 701285615718 |
12 | 283780a45637 |
13 | 1167c5288791 |
14 | 6cb425db375 |
15 | 37064b6bdd1 |
hex | 1d1b148614b |
2000134103371 has 2 divisors, whose sum is σ = 2000134103372. Its totient is φ = 2000134103370.
The previous prime is 2000134103281. The next prime is 2000134103393. The reversal of 2000134103371 is 1733014310002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2000134103371 - 27 = 2000134103243 is a prime.
It is a super-2 number, since 2×20001341033712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2000134103771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000067051685 + 1000067051686.
It is an arithmetic number, because the mean of its divisors is an integer number (1000067051686).
Almost surely, 22000134103371 is an apocalyptic number.
2000134103371 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000134103371 is an equidigital number, since it uses as much as digits as its factorization.
2000134103371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 2000134103371 its reverse (1733014310002), we get a palindrome (3733148413373).
The spelling of 2000134103371 in words is "two trillion, one hundred thirty-four million, one hundred three thousand, three hundred seventy-one".
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