2000143111 has 4 divisors (see below), whose sum is σ = 2006969832. Its totient is φ = 1993316392.

The previous prime is 2000143051. The next prime is 2000143127. The reversal of 2000143111 is 1113410002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2000143111 - 2¹³ = 2000134919 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2000143091 and 2000143100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000143511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3412921 + ... + 3413506.

It is an arithmetic number, because the mean of its divisors is an integer number (501742458).

Almost surely, 2^2000143111 is an apocalyptic number.

2000143111 is a deficient number, since it is larger than the sum of its proper divisors (6826721).

2000143111 is an equidigital number, since it uses as much as digits as its factorization.

2000143111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6826720.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 2000143111 is about 44722.9595509957. The cubic root of 2000143111 is about 1259.9511006050.

Adding to 2000143111 its reverse (1113410002), we get a palindrome (3113553113).

The spelling of 2000143111 in words is "two billion, one hundred forty-three thousand, one hundred eleven".