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20002011111983 = 21123194692593
BaseRepresentation
bin1001000110001000101001…
…10001000110001000101111
32121211011200112201120122202
410203010110301012020233
510110203104321040413
6110312444055132115
74133045324134055
oct443042461061057
977734615646582
1020002011111983
11641189490425a
1222b063507403b
13b21248b4bb24
144d21613aa1d5
1524a4716e0e58
hex123114c4622f

20002011111983 has 4 divisors (see below), whose sum is σ = 20002106015808. Its totient is φ = 20001916208160.

The previous prime is 20002011111977. The next prime is 20002011112033. The reversal of 20002011111983 is 38911111020002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20002011111983 - 212 = 20002011107887 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20002011113983) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47135066 + ... + 47557527.

It is an arithmetic number, because the mean of its divisors is an integer number (5000526503952).

Almost surely, 220002011111983 is an apocalyptic number.

20002011111983 is a deficient number, since it is larger than the sum of its proper divisors (94903825).

20002011111983 is an equidigital number, since it uses as much as digits as its factorization.

20002011111983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94903824.

The product of its (nonzero) digits is 864, while the sum is 29.

Adding to 20002011111983 its reverse (38911111020002), we get a palindrome (58913122131985).

The spelling of 20002011111983 in words is "twenty trillion, two billion, eleven million, one hundred eleven thousand, nine hundred eighty-three".

Divisors: 1 211231 94692593 20002011111983