Base | Representation |
---|---|
bin | 1001000110001000101001… |
… | …10001000110001000101111 |
3 | 2121211011200112201120122202 |
4 | 10203010110301012020233 |
5 | 10110203104321040413 |
6 | 110312444055132115 |
7 | 4133045324134055 |
oct | 443042461061057 |
9 | 77734615646582 |
10 | 20002011111983 |
11 | 641189490425a |
12 | 22b063507403b |
13 | b21248b4bb24 |
14 | 4d21613aa1d5 |
15 | 24a4716e0e58 |
hex | 123114c4622f |
20002011111983 has 4 divisors (see below), whose sum is σ = 20002106015808. Its totient is φ = 20001916208160.
The previous prime is 20002011111977. The next prime is 20002011112033. The reversal of 20002011111983 is 38911111020002.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20002011111983 - 212 = 20002011107887 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20002011113983) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47135066 + ... + 47557527.
It is an arithmetic number, because the mean of its divisors is an integer number (5000526503952).
Almost surely, 220002011111983 is an apocalyptic number.
20002011111983 is a deficient number, since it is larger than the sum of its proper divisors (94903825).
20002011111983 is an equidigital number, since it uses as much as digits as its factorization.
20002011111983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94903824.
The product of its (nonzero) digits is 864, while the sum is 29.
Adding to 20002011111983 its reverse (38911111020002), we get a palindrome (58913122131985).
The spelling of 20002011111983 in words is "twenty trillion, two billion, eleven million, one hundred eleven thousand, nine hundred eighty-three".
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