Base | Representation |
---|---|
bin | 101101011110110101101010… |
… | …110101111110010101000001 |
3 | 222020020210202112101212200001 |
4 | 231132311222311332111001 |
5 | 202204303102412113213 |
6 | 1545233040155400001 |
7 | 60063533124363316 |
oct | 5536655265762501 |
9 | 866223675355601 |
10 | 200031304410433 |
11 | 58810888597231 |
12 | 1a5274a7153001 |
13 | 877cb42974572 |
14 | 37577d13bad0d |
15 | 181d41747a1dd |
hex | b5ed6ad7e541 |
200031304410433 has 2 divisors, whose sum is σ = 200031304410434. Its totient is φ = 200031304410432.
The previous prime is 200031304410409. The next prime is 200031304410563. The reversal of 200031304410433 is 334014403130002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 148779908866369 + 51251395544064 = 12197537^2 + 7159008^2 .
It is a cyclic number.
It is not a de Polignac number, because 200031304410433 - 217 = 200031304279361 is a prime.
It is not a weakly prime, because it can be changed into another prime (200031304440433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100015652205216 + 100015652205217.
It is an arithmetic number, because the mean of its divisors is an integer number (100015652205217).
Almost surely, 2200031304410433 is an apocalyptic number.
It is an amenable number.
200031304410433 is a deficient number, since it is larger than the sum of its proper divisors (1).
200031304410433 is an equidigital number, since it uses as much as digits as its factorization.
200031304410433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 200031304410433 its reverse (334014403130002), we get a palindrome (534045707540435).
The spelling of 200031304410433 in words is "two hundred trillion, thirty-one billion, three hundred four million, four hundred ten thousand, four hundred thirty-three".
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