Base | Representation |
---|---|
bin | 1001000110001010110111… |
… | …01000011000110010101001 |
3 | 2121211021202101211221002201 |
4 | 10203011123220120302221 |
5 | 10110213023200331213 |
6 | 110313202045300201 |
7 | 4133116641460162 |
oct | 443053350306251 |
9 | 77737671757081 |
10 | 20003200011433 |
11 | 6412344a18a91 |
12 | 22b0907264661 |
13 | b213a8257822 |
14 | 4d223524a769 |
15 | 24a4e0c876dd |
hex | 12315ba18ca9 |
20003200011433 has 2 divisors, whose sum is σ = 20003200011434. Its totient is φ = 20003200011432.
The previous prime is 20003200011371. The next prime is 20003200011439. The reversal of 20003200011433 is 33411000230002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19803817221904 + 199382789529 = 4450148^2 + 446523^2 .
It is a cyclic number.
It is not a de Polignac number, because 20003200011433 - 217 = 20003199880361 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20003200011433.
It is not a weakly prime, because it can be changed into another prime (20003200011439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001600005716 + 10001600005717.
It is an arithmetic number, because the mean of its divisors is an integer number (10001600005717).
Almost surely, 220003200011433 is an apocalyptic number.
It is an amenable number.
20003200011433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20003200011433 is an equidigital number, since it uses as much as digits as its factorization.
20003200011433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 20003200011433 its reverse (33411000230002), we get a palindrome (53414200241435).
The spelling of 20003200011433 in words is "twenty trillion, three billion, two hundred million, eleven thousand, four hundred thirty-three".
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