Base | Representation |
---|---|
bin | 1001000110001010111001… |
… | …11000110101101100001011 |
3 | 2121211021210212112101222202 |
4 | 10203011130320311230023 |
5 | 10110213044100220243 |
6 | 110313204121310415 |
7 | 4133120315645555 |
oct | 443053470655413 |
9 | 77737725471882 |
10 | 20003221101323 |
11 | 6412355913149 |
12 | 22b091233540b |
13 | b213ac730055 |
14 | 4d2237d7a4d5 |
15 | 24a4e2a514b8 |
hex | 12315ce35b0b |
20003221101323 has 2 divisors, whose sum is σ = 20003221101324. Its totient is φ = 20003221101322.
The previous prime is 20003221101289. The next prime is 20003221101341. The reversal of 20003221101323 is 32310112230002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20003221101323 - 212 = 20003221097227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20003221101295 and 20003221101304.
It is not a weakly prime, because it can be changed into another prime (20003221901323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001610550661 + 10001610550662.
It is an arithmetic number, because the mean of its divisors is an integer number (10001610550662).
Almost surely, 220003221101323 is an apocalyptic number.
20003221101323 is a deficient number, since it is larger than the sum of its proper divisors (1).
20003221101323 is an equidigital number, since it uses as much as digits as its factorization.
20003221101323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 20003221101323 its reverse (32310112230002), we get a palindrome (52313333331325).
The spelling of 20003221101323 in words is "twenty trillion, three billion, two hundred twenty-one million, one hundred one thousand, three hundred twenty-three".
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