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2000331317455 = 51217328731523
BaseRepresentation
bin11101000110111101000…
…010011010000011001111
321002020012112021112001221
4131012331002122003033
5230233134304124310
64130534534144211
7264343034441122
oct35067502320317
97066175245057
102000331317455
11701376975569
12283816ab2067
131168270a89c3
146cb608963b9
1537077125ada
hex1d1bd09a0cf

2000331317455 has 8 divisors (see below), whose sum is σ = 2402369977392. Its totient is φ = 1598950123008.

The previous prime is 2000331317431. The next prime is 2000331317489. The reversal of 2000331317455 is 5547131330002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2000331317455 - 29 = 2000331316943 is a prime.

It is a super-4 number, since 4×20003313174554 (a number of 50 digits) contains 4444 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2000331317455.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 164359677 + ... + 164371846.

It is an arithmetic number, because the mean of its divisors is an integer number (300296247174).

Almost surely, 22000331317455 is an apocalyptic number.

2000331317455 is a deficient number, since it is larger than the sum of its proper divisors (402038659937).

2000331317455 is a wasteful number, since it uses less digits than its factorization.

2000331317455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 328732745.

The product of its (nonzero) digits is 37800, while the sum is 34.

Adding to 2000331317455 its reverse (5547131330002), we get a palindrome (7547462647457).

The spelling of 2000331317455 in words is "two trillion, three hundred thirty-one million, three hundred seventeen thousand, four hundred fifty-five".

Divisors: 1 5 1217 6085 328731523 1643657615 400066263491 2000331317455