2000335 has 4 divisors (see below), whose sum is σ = 2400408. Its totient is φ = 1600264.

The previous prime is 2000329. The next prime is 2000351. The reversal of 2000335 is 5330002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5330002 = 2 ⋅2665001.

It is a cyclic number.

It is not a de Polignac number, because 2000335 - 2⁵ = 2000303 is a prime.

It is a super-2 number, since 2×2000335² = 8002680224450, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200029 + ... + 200038.

It is an arithmetic number, because the mean of its divisors is an integer number (600102).

2^2000335 is an apocalyptic number.

2000335 is a deficient number, since it is larger than the sum of its proper divisors (400073).

2000335 is an equidigital number, since it uses as much as digits as its factorization.

2000335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400072.

The product of its (nonzero) digits is 90, while the sum is 13.

The square root of 2000335 is about 1414.3319977997. The cubic root of 2000335 is about 125.9991391560. Note that the first 3 decimals are identical.

Adding to 2000335 its reverse (5330002), we get a palindrome (7330337).

The spelling of 2000335 in words is "two million, three hundred thirty-five", and thus it is an aban number.