Search a number
-
+
20003513165473 is a prime number
BaseRepresentation
bin1001000110001011011100…
…10010111110011010100001
32121211022120020002210200111
410203011232102332122201
510110214143332243343
6110313253113251321
74133130463313545
oct443055622763241
977738506083614
1020003513165473
116412495767282
1222b0994103b41
13b214280ac986
144d2264a85a25
1524a50d4e3c9d
hex12316e4be6a1

20003513165473 has 2 divisors, whose sum is σ = 20003513165474. Its totient is φ = 20003513165472.

The previous prime is 20003513165453. The next prime is 20003513165501. The reversal of 20003513165473 is 37456131530002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12345054683809 + 7658458481664 = 3513553^2 + 2767392^2 .

It is a cyclic number.

It is not a de Polignac number, because 20003513165473 - 233 = 19994923230881 is a prime.

It is a super-2 number, since 2×200035131654732 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20003513165453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001756582736 + 10001756582737.

It is an arithmetic number, because the mean of its divisors is an integer number (10001756582737).

Almost surely, 220003513165473 is an apocalyptic number.

It is an amenable number.

20003513165473 is a deficient number, since it is larger than the sum of its proper divisors (1).

20003513165473 is an equidigital number, since it uses as much as digits as its factorization.

20003513165473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 40.

Adding to 20003513165473 its reverse (37456131530002), we get a palindrome (57459644695475).

The spelling of 20003513165473 in words is "twenty trillion, three billion, five hundred thirteen million, one hundred sixty-five thousand, four hundred seventy-three".