Base | Representation |
---|---|
bin | 101101011111000000110111… |
… | …101100101000011101100001 |
3 | 222020021221210200222101021221 |
4 | 231133000313230220131201 |
5 | 202210002220243203231 |
6 | 1545242345424015041 |
7 | 60064440142542034 |
oct | 5537006754503541 |
9 | 866257720871257 |
10 | 200043331225441 |
11 | 5881599a3a3370 |
12 | 1a5298a2a61481 |
13 | 878100b537452 |
14 | 37582127b901b |
15 | 181d8bd245d11 |
hex | b5f037b28761 |
200043331225441 has 16 divisors (see below), whose sum is σ = 223533602922240. Its totient is φ = 177460108519680.
The previous prime is 200043331225277. The next prime is 200043331225447. The reversal of 200043331225441 is 144522133340002.
It is a cyclic number.
It is not a de Polignac number, because 200043331225441 - 215 = 200043331192673 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200043331225397 and 200043331225406.
It is not an unprimeable number, because it can be changed into a prime (200043331225447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 573907386 + ... + 574255843.
It is an arithmetic number, because the mean of its divisors is an integer number (13970850182640).
Almost surely, 2200043331225441 is an apocalyptic number.
It is an amenable number.
200043331225441 is a deficient number, since it is larger than the sum of its proper divisors (23490271696799).
200043331225441 is a wasteful number, since it uses less digits than its factorization.
200043331225441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1148163624.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 200043331225441 its reverse (144522133340002), we get a palindrome (344565464565443).
The spelling of 200043331225441 in words is "two hundred trillion, forty-three billion, three hundred thirty-one million, two hundred twenty-five thousand, four hundred forty-one".
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