Base | Representation |
---|---|
bin | 1001000110001101000001… |
… | …00100101010000100011011 |
3 | 2121211101202000021211202020 |
4 | 10203012200210222010123 |
5 | 10110222410301132111 |
6 | 110313512524305523 |
7 | 4133160415025664 |
oct | 443064044520433 |
9 | 77741660254666 |
10 | 20004356661531 |
11 | 6412888906360 |
12 | 22b0b8a6a22a3 |
13 | b21530a81778 |
14 | 4d2304ad436b |
15 | 24a55c5ad906 |
hex | 1231a092a11b |
20004356661531 has 64 divisors (see below), whose sum is σ = 31397407888896. Its totient is φ = 11192799488000.
The previous prime is 20004356661517. The next prime is 20004356661551. The reversal of 20004356661531 is 13516665340002.
It is not a de Polignac number, because 20004356661531 - 26 = 20004356661467 is a prime.
It is a super-3 number, since 3×200043566615313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (20004356661551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 132266005 + ... + 132417161.
It is an arithmetic number, because the mean of its divisors is an integer number (490584498264).
Almost surely, 220004356661531 is an apocalyptic number.
20004356661531 is a deficient number, since it is larger than the sum of its proper divisors (11393051227365).
20004356661531 is a wasteful number, since it uses less digits than its factorization.
20004356661531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 155692.
The product of its (nonzero) digits is 388800, while the sum is 42.
The spelling of 20004356661531 in words is "twenty trillion, four billion, three hundred fifty-six million, six hundred sixty-one thousand, five hundred thirty-one".
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