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2000524044341 = 13133569454919
BaseRepresentation
bin11101000111001000100…
…001100110100000110101
321002020200221221001122202
4131013020201212200311
5230234033123404331
64131010021034245
7264350564544104
oct35071041464065
97066627831582
102000524044341
11701465740089
1228386b555985
13116857cb7694
146cb7c30403b
1537088ee4ecb
hex1d1c8866835

2000524044341 has 8 divisors (see below), whose sum is σ = 2015859700800. Its totient is φ = 1985189365120.

The previous prime is 2000524044331. The next prime is 2000524044397. The reversal of 2000524044341 is 1434404250002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2000524044341 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000524044331) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4170080 + ... + 4624998.

It is an arithmetic number, because the mean of its divisors is an integer number (251982462600).

Almost surely, 22000524044341 is an apocalyptic number.

It is an amenable number.

2000524044341 is a deficient number, since it is larger than the sum of its proper divisors (15335656459).

2000524044341 is a wasteful number, since it uses less digits than its factorization.

2000524044341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 488619.

The product of its (nonzero) digits is 15360, while the sum is 29.

Adding to 2000524044341 its reverse (1434404250002), we get a palindrome (3434928294343).

The spelling of 2000524044341 in words is "two trillion, five hundred twenty-four million, forty-four thousand, three hundred forty-one".

Divisors: 1 131 33569 454919 4397539 59594389 15271175911 2000524044341