Base | Representation |
---|---|
bin | 101101011111110110101101… |
… | …100000100000001011010010 |
3 | 222020111111000122202212212221 |
4 | 231133312231200200023102 |
5 | 202211424114414111424 |
6 | 1545325110140411254 |
7 | 60101554563046402 |
oct | 5537665540401322 |
9 | 866444018685787 |
10 | 200101142332114 |
11 | 58838466247481 |
12 | 1a538b37846b2a |
13 | 87865c265148a |
14 | 375ad38682802 |
15 | 18201537229e4 |
hex | b5fdad8202d2 |
200101142332114 has 8 divisors (see below), whose sum is σ = 301723188438528. Its totient is φ = 99526746185940.
The previous prime is 200101142332093. The next prime is 200101142332121. The reversal of 200101142332114 is 411233241101002.
200101142332114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261912489582 + ... + 261912490345.
It is an arithmetic number, because the mean of its divisors is an integer number (37715398554816).
Almost surely, 2200101142332114 is an apocalyptic number.
200101142332114 is a deficient number, since it is larger than the sum of its proper divisors (101622046106414).
200101142332114 is a wasteful number, since it uses less digits than its factorization.
200101142332114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 523824980120.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 200101142332114 its reverse (411233241101002), we get a palindrome (611334383433116).
The spelling of 200101142332114 in words is "two hundred trillion, one hundred one billion, one hundred forty-two million, three hundred thirty-two thousand, one hundred fourteen".
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