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2001011983 = 23659132019
BaseRepresentation
bin111011101000101…
…0000010100001111
312011110020221101221
41313101100110033
513044224340413
6530320344211
7100405215115
oct16721202417
95143227357
102001011983
11937578a13
1247a175067
1325b73cb79
1414da7dab5
15baa1268d
hex7745050f

2001011983 has 8 divisors (see below), whose sum is σ = 2091196800. Its totient is φ = 1911092568.

The previous prime is 2001011941. The next prime is 2001012001. The reversal of 2001011983 is 3891101002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2001011983 - 221 = 1998914831 is a prime.

It is a super-2 number, since 2×20010119832 = 8008097912219184578, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2001011083) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50853 + ... + 81166.

It is an arithmetic number, because the mean of its divisors is an integer number (261399600).

Almost surely, 22001011983 is an apocalyptic number.

2001011983 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

2001011983 is a deficient number, since it is larger than the sum of its proper divisors (90184817).

2001011983 is a wasteful number, since it uses less digits than its factorization.

2001011983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132701.

The product of its (nonzero) digits is 432, while the sum is 25.

The square root of 2001011983 is about 44732.6724330215. The cubic root of 2001011983 is about 1260.1335171773.

Adding to 2001011983 its reverse (3891101002), we get a palindrome (5892112985).

The spelling of 2001011983 in words is "two billion, one million, eleven thousand, nine hundred eighty-three".

Divisors: 1 23 659 15157 132019 3036437 87000521 2001011983