Base | Representation |
---|---|
bin | 11101000111100101101… |
… | …111110100100110001101 |
3 | 21002021222010110012111121 |
4 | 131013211233310212031 |
5 | 230241034130430214 |
6 | 4131130413120541 |
7 | 264366000002626 |
oct | 35074557644615 |
9 | 7067863405447 |
10 | 2001014311309 |
11 | 7016974599a2 |
12 | 283987789151 |
13 | 116905742590 |
14 | 6cbc7484a4d |
15 | 370b7089424 |
hex | 1d1e5bf498d |
2001014311309 has 4 divisors (see below), whose sum is σ = 2154938489116. Its totient is φ = 1847090133504.
The previous prime is 2001014311229. The next prime is 2001014311327. The reversal of 2001014311309 is 9031134101002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 178757303209 + 1822257008100 = 422797^2 + 1349910^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001014311309 - 29 = 2001014310797 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001014311339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76962088884 + ... + 76962088909.
It is an arithmetic number, because the mean of its divisors is an integer number (538734622279).
Almost surely, 22001014311309 is an apocalyptic number.
It is an amenable number.
2001014311309 is a deficient number, since it is larger than the sum of its proper divisors (153924177807).
2001014311309 is a wasteful number, since it uses less digits than its factorization.
2001014311309 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153924177806.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 2001014311309 in words is "two trillion, one billion, fourteen million, three hundred eleven thousand, three hundred nine".
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