Base | Representation |
---|---|
bin | 11101000111100110001… |
… | …101001100101011110011 |
3 | 21002021222122221110001211 |
4 | 131013212031030223303 |
5 | 230241043113342042 |
6 | 4131131250140551 |
7 | 264366122315224 |
oct | 35074615145363 |
9 | 7067878843054 |
10 | 2001022012147 |
11 | 7016a0839724 |
12 | 28398a281757 |
13 | 11690720a7a2 |
14 | 6cbc84cb24b |
15 | 370b7aab017 |
hex | 1d1e634caf3 |
2001022012147 has 2 divisors, whose sum is σ = 2001022012148. Its totient is φ = 2001022012146.
The previous prime is 2001022012097. The next prime is 2001022012153. The reversal of 2001022012147 is 7412102201002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001022012147 - 219 = 2001021487859 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001022312147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000511006073 + 1000511006074.
It is an arithmetic number, because the mean of its divisors is an integer number (1000511006074).
Almost surely, 22001022012147 is an apocalyptic number.
2001022012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001022012147 is an equidigital number, since it uses as much as digits as its factorization.
2001022012147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 22.
Adding to 2001022012147 its reverse (7412102201002), we get a palindrome (9413124213149).
The spelling of 2001022012147 in words is "two trillion, one billion, twenty-two million, twelve thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •