20011001222081 has 2 divisors, whose sum is σ = 20011001222082. Its totient is φ = 20011001222080.

The previous prime is 20011001222063. The next prime is 20011001222117. The reversal of 20011001222081 is 18022210011002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15605028102400 + 4405973119681 = 3950320^2 + 2099041^2 .

It is a cyclic number.

It is not a de Polignac number, because 20011001222081 - 2³⁸ = 19736123315137 is a prime.

It is a super-3 number, since 3×20011001222081³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (20011001222011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005500611040 + 10005500611041.

It is an arithmetic number, because the mean of its divisors is an integer number (10005500611041).

Almost surely, 2^{20011001222081} is an apocalyptic number.

It is an amenable number.

20011001222081 is a deficient number, since it is larger than the sum of its proper divisors (1).

20011001222081 is an equidigital number, since it uses as much as digits as its factorization.

20011001222081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 20011001222081 its reverse (18022210011002), we get a palindrome (38033211233083).

The spelling of 20011001222081 in words is "twenty trillion, eleven billion, one million, two hundred twenty-two thousand, eighty-one".