Base | Representation |
---|---|
bin | 10010101000101111… |
… | …111101100010011110 |
3 | 1220122121020212000212 |
4 | 102220233331202132 |
5 | 311440304424202 |
6 | 13105401252422 |
7 | 1305614546366 |
oct | 225057754236 |
9 | 56577225025 |
10 | 20011014302 |
11 | 8539772254 |
12 | 3a65794112 |
13 | 1b6ba63086 |
14 | d7b9519a6 |
15 | 7c1be4652 |
hex | 4a8bfd89e |
20011014302 has 4 divisors (see below), whose sum is σ = 30016521456. Its totient is φ = 10005507150.
The previous prime is 20011014293. The next prime is 20011014329. The reversal of 20011014302 is 20341011002.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×200110143023 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002753574 + ... + 5002753577.
It is an arithmetic number, because the mean of its divisors is an integer number (7504130364).
Almost surely, 220011014302 is an apocalyptic number.
20011014302 is a deficient number, since it is larger than the sum of its proper divisors (10005507154).
20011014302 is a wasteful number, since it uses less digits than its factorization.
20011014302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10005507153.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 20011014302 its reverse (20341011002), we get a palindrome (40352025304).
It can be divided in two parts, 200110 and 14302, that added together give a palindrome (214412).
The spelling of 20011014302 in words is "twenty billion, eleven million, fourteen thousand, three hundred two".
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