Base | Representation |
---|---|
bin | 10010101000110000… |
… | …010101101100100011 |
3 | 1220122121102212202122 |
4 | 102220300111230203 |
5 | 311440321111001 |
6 | 13105403334455 |
7 | 1305615441023 |
oct | 225060255443 |
9 | 56577385678 |
10 | 20011113251 |
11 | 853982a628 |
12 | 3a6582142b |
13 | 1b6ba9911c |
14 | d7b979a83 |
15 | 7c1c13b1b |
hex | 4a8c15b23 |
20011113251 has 2 divisors, whose sum is σ = 20011113252. Its totient is φ = 20011113250.
The previous prime is 20011113121. The next prime is 20011113323. The reversal of 20011113251 is 15231111002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20011113251 - 226 = 19944004387 is a prime.
It is not a weakly prime, because it can be changed into another prime (20011013251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005556625 + 10005556626.
It is an arithmetic number, because the mean of its divisors is an integer number (10005556626).
Almost surely, 220011113251 is an apocalyptic number.
20011113251 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011113251 is an equidigital number, since it uses as much as digits as its factorization.
20011113251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 20011113251 its reverse (15231111002), we get a palindrome (35242224253).
The spelling of 20011113251 in words is "twenty billion, eleven million, one hundred thirteen thousand, two hundred fifty-one".
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