Base | Representation |
---|---|
bin | 11101000111101011100… |
… | …100111110011000111100 |
3 | 21002022012221111222002000 |
4 | 131013223210332120330 |
5 | 230241234201144012 |
6 | 4131144225502300 |
7 | 264401265314622 |
oct | 35075344763074 |
9 | 7068187458060 |
10 | 2001112131132 |
11 | 7017376a1424 |
12 | 2839b44a1990 |
13 | 11691caa192a |
14 | 6cbd6469512 |
15 | 370c095cddc |
hex | 1d1eb93e63c |
2001112131132 has 48 divisors (see below), whose sum is σ = 5192949377280. Its totient is φ = 666409834224.
The previous prime is 2001112131127. The next prime is 2001112131149. The reversal of 2001112131132 is 2311312111002.
2001112131132 is a `hidden beast` number, since 200 + 1 + 1 + 121 + 311 + 32 = 666.
It is a super-2 number, since 2×20011121311322 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8600538 + ... + 8830145.
It is an arithmetic number, because the mean of its divisors is an integer number (108186445360).
Almost surely, 22001112131132 is an apocalyptic number.
It is an amenable number.
2001112131132 is an abundant number, since it is smaller than the sum of its proper divisors (3191837246148).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2001112131132 is a wasteful number, since it uses less digits than its factorization.
2001112131132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17431759 (or 17431751 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 2001112131132 its reverse (2311312111002), we get a palindrome (4312424242134).
The spelling of 2001112131132 in words is "two trillion, one billion, one hundred twelve million, one hundred thirty-one thousand, one hundred thirty-two".
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