Base | Representation |
---|---|
bin | 1001000110011001100111… |
… | …10001110010100000010001 |
3 | 2121212001012110012012101121 |
4 | 10203030303301302200101 |
5 | 10110330234024301001 |
6 | 110320552054402241 |
7 | 4133520145503115 |
oct | 443146361624021 |
9 | 77761173165347 |
10 | 20011121322001 |
11 | 641573a32a947 |
12 | 22b2358060381 |
13 | b2206b3a8c44 |
14 | 4d27872ad745 |
15 | 24a8063dc6a1 |
hex | 123333c72811 |
20011121322001 has 2 divisors, whose sum is σ = 20011121322002. Its totient is φ = 20011121322000.
The previous prime is 20011121321959. The next prime is 20011121322097. The reversal of 20011121322001 is 10022312111002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19959235315776 + 51886006225 = 4467576^2 + 227785^2 .
It is a cyclic number.
It is not a de Polignac number, because 20011121322001 - 213 = 20011121313809 is a prime.
It is not a weakly prime, because it can be changed into another prime (20011128322001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005560661000 + 10005560661001.
It is an arithmetic number, because the mean of its divisors is an integer number (10005560661001).
Almost surely, 220011121322001 is an apocalyptic number.
It is an amenable number.
20011121322001 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011121322001 is an equidigital number, since it uses as much as digits as its factorization.
20011121322001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 20011121322001 its reverse (10022312111002), we get a palindrome (30033433433003).
The spelling of 20011121322001 in words is "twenty trillion, eleven billion, one hundred twenty-one million, three hundred twenty-two thousand, one".
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