Base | Representation |
---|---|
bin | 11101000111101011101… |
… | …000010111011110001101 |
3 | 21002022020000012010210012 |
4 | 131013223220113132031 |
5 | 230241234413122201 |
6 | 4131144300523005 |
7 | 264401306010143 |
oct | 35075350273615 |
9 | 7068200163705 |
10 | 2001113020301 |
11 | 70173814947a |
12 | 2839b4850465 |
13 | 116920023575 |
14 | 6cbd661b593 |
15 | 370c0a865bb |
hex | 1d1eba1778d |
2001113020301 has 4 divisors (see below), whose sum is σ = 2020926020604. Its totient is φ = 1981300020000.
The previous prime is 2001113020297. The next prime is 2001113020327. The reversal of 2001113020301 is 1030203111002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1883621747401 + 117491272900 = 1372451^2 + 342770^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001113020301 - 22 = 2001113020297 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001113020381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9906500000 + ... + 9906500201.
It is an arithmetic number, because the mean of its divisors is an integer number (505231505151).
Almost surely, 22001113020301 is an apocalyptic number.
It is an amenable number.
2001113020301 is a deficient number, since it is larger than the sum of its proper divisors (19813000303).
2001113020301 is a wasteful number, since it uses less digits than its factorization.
2001113020301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19813000302.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 2001113020301 its reverse (1030203111002), we get a palindrome (3031316131303).
The spelling of 2001113020301 in words is "two trillion, one billion, one hundred thirteen million, twenty thousand, three hundred one".
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