Base | Representation |
---|---|
bin | 10010011100111100… |
… | …100110010000001001 |
3 | 1220010210122200202021 |
4 | 102130330212100021 |
5 | 311034112001301 |
6 | 13034005204441 |
7 | 1300661502661 |
oct | 223474462011 |
9 | 56123580667 |
10 | 19813000201 |
11 | 8447a16335 |
12 | 3a0b400721 |
13 | 1b39a22977 |
14 | d5d5291a1 |
15 | 7ae62d8a1 |
hex | 49cf26409 |
19813000201 has 2 divisors, whose sum is σ = 19813000202. Its totient is φ = 19813000200.
The previous prime is 19813000169. The next prime is 19813000223. The reversal of 19813000201 is 10200031891.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19398918400 + 414081801 = 139280^2 + 20349^2 .
It is a cyclic number.
It is not a de Polignac number, because 19813000201 - 25 = 19813000169 is a prime.
It is a super-3 number, since 3×198130002013 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (19813000231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9906500100 + 9906500101.
It is an arithmetic number, because the mean of its divisors is an integer number (9906500101).
Almost surely, 219813000201 is an apocalyptic number.
It is an amenable number.
19813000201 is a deficient number, since it is larger than the sum of its proper divisors (1).
19813000201 is an equidigital number, since it uses as much as digits as its factorization.
19813000201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 19813000201 in words is "nineteen billion, eight hundred thirteen million, two hundred one", and thus it is an aban number.
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