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200111311211312 = 2412506956950707
BaseRepresentation
bin101101100000000000001011…
…100111101100101100110000
3222020112110021100022110201102
4231200000023213230230300
5202212110431132230222
61545333511155023532
760102364561101464
oct5540001347545460
9866473240273642
10200111311211312
1158841804318976
121a53aab529aba8
13878755331aa67
14375b6210064a4
15182054b33dd92
hexb6000b9ecb30

200111311211312 has 10 divisors (see below), whose sum is σ = 387715665471948. Its totient is φ = 100055655605648.

The previous prime is 200111311211311. The next prime is 200111311211323. The reversal of 200111311211312 is 213112113111002.

200111311211312 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×2001113112113122 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (200111311211311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6253478475338 + ... + 6253478475369.

Almost surely, 2200111311211312 is an apocalyptic number.

It is an amenable number.

200111311211312 is a deficient number, since it is larger than the sum of its proper divisors (187604354260636).

200111311211312 is a wasteful number, since it uses less digits than its factorization.

200111311211312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12506956950715 (or 12506956950709 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 200111311211312 its reverse (213112113111002), we get a palindrome (413223424322314).

The spelling of 200111311211312 in words is "two hundred trillion, one hundred eleven billion, three hundred eleven million, two hundred eleven thousand, three hundred twelve".

Divisors: 1 2 4 8 16 12506956950707 25013913901414 50027827802828 100055655605656 200111311211312