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2001113313000 = 233534725156543
BaseRepresentation
bin11101000111101011101…
…001011110111011101000
321002022020000202000021220
4131013223221132323220
5230241240002004000
64131144311102040
7264401311336404
oct35075351367350
97068200660256
102001113313000
1170173832937a
122839b4971920
131169200c6869
146cbd6696104
15370c0ae31a0
hex1d1eba5eee8

2001113313000 has 256 divisors, whose sum is σ = 6401830256640. Its totient is φ = 520186400000.

The previous prime is 2001113312963. The next prime is 2001113313013. The reversal of 2001113313000 is 3133111002.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 35362729 + ... + 35419271.

It is an arithmetic number, because the mean of its divisors is an integer number (25007149440).

Almost surely, 22001113313000 is an apocalyptic number.

2001113313000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2001113313000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3200915128320).

2001113313000 is an abundant number, since it is smaller than the sum of its proper divisors (4400716943640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2001113313000 is a wasteful number, since it uses less digits than its factorization.

2001113313000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56865 (or 56851 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 2001113313000 its reverse (3133111002), we get a palindrome (2004246424002).

The spelling of 2001113313000 in words is "two trillion, one billion, one hundred thirteen million, three hundred thirteen thousand".