Base | Representation |
---|---|
bin | 11101000111101011110… |
… | …000100000001110011011 |
3 | 21002022020011012111201102 |
4 | 131013223300200032123 |
5 | 230241240434401212 |
6 | 4131144414342015 |
7 | 264401333102624 |
oct | 35075360401633 |
9 | 7068204174642 |
10 | 2001115153307 |
11 | 701739375a96 |
12 | 2839b54ba90b |
13 | 1169205bc3ba |
14 | 6cbd6a14a4b |
15 | 370c0d585c2 |
hex | 1d1ebc2039b |
2001115153307 has 2 divisors, whose sum is σ = 2001115153308. Its totient is φ = 2001115153306.
The previous prime is 2001115153231. The next prime is 2001115153333. The reversal of 2001115153307 is 7033515111002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001115153307 - 230 = 2000041411483 is a prime.
It is a super-2 number, since 2×20011151533072 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2001115153307.
It is not a weakly prime, because it can be changed into another prime (2001115153357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000557576653 + 1000557576654.
It is an arithmetic number, because the mean of its divisors is an integer number (1000557576654).
Almost surely, 22001115153307 is an apocalyptic number.
2001115153307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001115153307 is an equidigital number, since it uses as much as digits as its factorization.
2001115153307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3150, while the sum is 29.
The spelling of 2001115153307 in words is "two trillion, one billion, one hundred fifteen million, one hundred fifty-three thousand, three hundred seven".
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