Base | Representation |
---|---|
bin | 1001000110011001110001… |
… | …00010100000001111001111 |
3 | 2121212001102000111110220212 |
4 | 10203030320202200033033 |
5 | 10110330420001413403 |
6 | 110321004030433035 |
7 | 4133522135453600 |
oct | 443147042401717 |
9 | 77761360443825 |
10 | 20011201201103 |
11 | 6415780429232 |
12 | 22b237a96277b |
13 | b22081ac6298 |
14 | 4d2793b43da7 |
15 | 24a80d41a4d8 |
hex | 1233388a03cf |
20011201201103 has 24 divisors (see below), whose sum is σ = 23359920968160. Its totient is φ = 17092446275520.
The previous prime is 20011201201097. The next prime is 20011201201171. The reversal of 20011201201103 is 30110210211002.
It is not a de Polignac number, because 20011201201103 - 28 = 20011201200847 is a prime.
It is a super-2 number, since 2×200112012011032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20011201201903) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15677513 + ... + 16905821.
It is an arithmetic number, because the mean of its divisors is an integer number (973330040340).
Almost surely, 220011201201103 is an apocalyptic number.
20011201201103 is a deficient number, since it is larger than the sum of its proper divisors (3348719767057).
20011201201103 is a wasteful number, since it uses less digits than its factorization.
20011201201103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1229487 (or 1229480 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 20011201201103 its reverse (30110210211002), we get a palindrome (50121411412105).
The spelling of 20011201201103 in words is "twenty trillion, eleven billion, two hundred one million, two hundred one thousand, one hundred three".
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