Base | Representation |
---|---|
bin | 1001000110011001110010… |
… | …00100100000000101111011 |
3 | 2121212001102122021021022001 |
4 | 10203030321010200011323 |
5 | 10110330424242112103 |
6 | 110321004545441431 |
7 | 4133522304303145 |
oct | 443147104400573 |
9 | 77761378237261 |
10 | 20011210113403 |
11 | 6415785466173 |
12 | 22b2381940277 |
13 | b220838c6a32 |
14 | 4d2794dc3c95 |
15 | 24a80e0cb01d |
hex | 12333912017b |
20011210113403 has 2 divisors, whose sum is σ = 20011210113404. Its totient is φ = 20011210113402.
The previous prime is 20011210113341. The next prime is 20011210113431. The reversal of 20011210113403 is 30431101211002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20011210113403 - 217 = 20011209982331 is a prime.
It is not a weakly prime, because it can be changed into another prime (20011210113443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005605056701 + 10005605056702.
It is an arithmetic number, because the mean of its divisors is an integer number (10005605056702).
Almost surely, 220011210113403 is an apocalyptic number.
20011210113403 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011210113403 is an equidigital number, since it uses as much as digits as its factorization.
20011210113403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 20011210113403 its reverse (30431101211002), we get a palindrome (50442311324405).
The spelling of 20011210113403 in words is "twenty trillion, eleven billion, two hundred ten million, one hundred thirteen thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •