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2001122105737 is a prime number
BaseRepresentation
bin11101000111101100001…
…011000001100110001001
321002022020122021201122211
4131013230023001212021
5230241244224340422
64131145223345121
7264401446150246
oct35075413014611
97068218251584
102001122105737
117017422944a7
122839b78b21a1
13116921b84a71
146cbd79045cd
15370c177d577
hex1d1ec2c1989

2001122105737 has 2 divisors, whose sum is σ = 2001122105738. Its totient is φ = 2001122105736.

The previous prime is 2001122105657. The next prime is 2001122105753. The reversal of 2001122105737 is 7375012211002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1507041043456 + 494081062281 = 1227616^2 + 702909^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2001122105737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2001122105699 and 2001122105708.

It is not a weakly prime, because it can be changed into another prime (2001122105797) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000561052868 + 1000561052869.

It is an arithmetic number, because the mean of its divisors is an integer number (1000561052869).

Almost surely, 22001122105737 is an apocalyptic number.

It is an amenable number.

2001122105737 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001122105737 is an equidigital number, since it uses as much as digits as its factorization.

2001122105737 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5880, while the sum is 31.

Adding to 2001122105737 its reverse (7375012211002), we get a palindrome (9376134316739).

The spelling of 2001122105737 in words is "two trillion, one billion, one hundred twenty-two million, one hundred five thousand, seven hundred thirty-seven".