Base | Representation |
---|---|
bin | 1001000110011001111100… |
… | …11111001101011111111101 |
3 | 2121212001122222021211221020 |
4 | 10203030332133031133331 |
5 | 10110331121024014323 |
6 | 110321021553454353 |
7 | 4133524456654164 |
oct | 443147637153775 |
9 | 77761588254836 |
10 | 20011301001213 |
11 | 64158217a3565 |
12 | 22b23a82713b9 |
13 | b22099699ac2 |
14 | 4d27a30c23db |
15 | 24a817080ae3 |
hex | 12333e7cd7fd |
20011301001213 has 4 divisors (see below), whose sum is σ = 26681734668288. Its totient is φ = 13340867334140.
The previous prime is 20011301001163. The next prime is 20011301001247. The reversal of 20011301001213 is 31210010311002.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20011301001213 - 29 = 20011301000701 is a prime.
It is a super-2 number, since 2×200113010012132 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20011301001192 and 20011301001201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20011301071213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3335216833533 + ... + 3335216833538.
It is an arithmetic number, because the mean of its divisors is an integer number (6670433667072).
Almost surely, 220011301001213 is an apocalyptic number.
It is an amenable number.
20011301001213 is a deficient number, since it is larger than the sum of its proper divisors (6670433667075).
20011301001213 is an equidigital number, since it uses as much as digits as its factorization.
20011301001213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6670433667074.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 20011301001213 its reverse (31210010311002), we get a palindrome (51221311312215).
The spelling of 20011301001213 in words is "twenty trillion, eleven billion, three hundred one million, one thousand, two hundred thirteen".
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