200113201201 has 4 divisors (see below), whose sum is σ = 200116140400. Its totient is φ = 200110262004.

The previous prime is 200113201111. The next prime is 200113201219. The reversal of 200113201201 is 102102311002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 102102311002 = 2 ⋅51051155501.

It is a cyclic number.

It is not a de Polignac number, because 200113201201 - 2¹³ = 200113193009 is a prime.

It is a super-3 number, since 3×200113201201³ (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200113201291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1364991 + ... + 1504468.

It is an arithmetic number, because the mean of its divisors is an integer number (50029035100).

Almost surely, 2^200113201201 is an apocalyptic number.

It is an amenable number.

200113201201 is a deficient number, since it is larger than the sum of its proper divisors (2939199).

200113201201 is an equidigital number, since it uses as much as digits as its factorization.

200113201201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2939198.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 200113201201 its reverse (102102311002), we get a palindrome (302215512203).

The spelling of 200113201201 in words is "two hundred billion, one hundred thirteen million, two hundred one thousand, two hundred one".