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2001132645593 is a prime number
BaseRepresentation
bin11101000111101100110…
…011001110110011011001
321002022021101010012121212
4131013230303032303121
5230241304424124333
64131150241312505
7264401634555554
oct35075463166331
97068241105555
102001132645593
11701748233224
122839bb335735
13116924105273
146cbd908969b
15370c2661448
hex1d1ecccecd9

2001132645593 has 2 divisors, whose sum is σ = 2001132645594. Its totient is φ = 2001132645592.

The previous prime is 2001132645541. The next prime is 2001132645643. The reversal of 2001132645593 is 3955462311002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1770091880704 + 231040764889 = 1330448^2 + 480667^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001132645593 - 26 = 2001132645529 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2001132645593.

It is not a weakly prime, because it can be changed into another prime (2001132545593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000566322796 + 1000566322797.

It is an arithmetic number, because the mean of its divisors is an integer number (1000566322797).

Almost surely, 22001132645593 is an apocalyptic number.

It is an amenable number.

2001132645593 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001132645593 is an equidigital number, since it uses as much as digits as its factorization.

2001132645593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 41.

Adding to 2001132645593 its reverse (3955462311002), we get a palindrome (5956594956595).

The spelling of 2001132645593 in words is "two trillion, one billion, one hundred thirty-two million, six hundred forty-five thousand, five hundred ninety-three".