200113301320133 has 4 divisors (see below), whose sum is σ = 200328708534540. Its totient is φ = 199897894105728.

The previous prime is 200113301320109. The next prime is 200113301320193. The reversal of 200113301320133 is 331023103311002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 48526799989924 + 151586501330209 = 6966118^2 + 12312047^2 .

It is a cyclic number.

It is not a de Polignac number, because 200113301320133 - 2³⁶ = 200044581843397 is a prime.

It is a super-2 number, since 2×200113301320133² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200113301320099 and 200113301320108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200113301320193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107703605810 + ... + 107703607667.

It is an arithmetic number, because the mean of its divisors is an integer number (50082177133635).

Almost surely, 2^{200113301320133} is an apocalyptic number.

It is an amenable number.

200113301320133 is a deficient number, since it is larger than the sum of its proper divisors (215407214407).

200113301320133 is an equidigital number, since it uses as much as digits as its factorization.

200113301320133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215407214406.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 200113301320133 its reverse (331023103311002), we get a palindrome (531136404631135).

The spelling of 200113301320133 in words is "two hundred trillion, one hundred thirteen billion, three hundred one million, three hundred twenty thousand, one hundred thirty-three".