Search a number
-
+
2001144857 = 8324110179
BaseRepresentation
bin111011101000111…
…0000110000011001
312011110111200200012
41313101300300121
513044243113412
6530323251305
7100406310365
oct16721606031
95143450605
102001144857
11937659828
1247a219b35
1325b7884aa
1414dab62a5
15baa3bc22
hex77470c19

2001144857 has 4 divisors (see below), whose sum is σ = 2025255120. Its totient is φ = 1977034596.

The previous prime is 2001144737. The next prime is 2001144863. The reversal of 2001144857 is 7584411002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2001144857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2001147857) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12055007 + ... + 12055172.

It is an arithmetic number, because the mean of its divisors is an integer number (506313780).

Almost surely, 22001144857 is an apocalyptic number.

It is an amenable number.

2001144857 is a deficient number, since it is larger than the sum of its proper divisors (24110263).

2001144857 is an equidigital number, since it uses as much as digits as its factorization.

2001144857 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24110262.

The product of its (nonzero) digits is 8960, while the sum is 32.

The square root of 2001144857 is about 44734.1576091470. The cubic root of 2001144857 is about 1260.1614089435.

Adding to 2001144857 its reverse (7584411002), we get a palindrome (9585555859).

The spelling of 2001144857 in words is "two billion, one million, one hundred forty-four thousand, eight hundred fifty-seven".

Divisors: 1 83 24110179 2001144857