20012013013 has 4 divisors (see below), whose sum is σ = 20199041280. Its totient is φ = 19824984748.

The previous prime is 20012013011. The next prime is 20012013019. The reversal of 20012013013 is 31031021002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31031021002 = 2 ⋅15515510501.

It is a cyclic number.

It is not a de Polignac number, because 20012013013 - 2¹ = 20012013011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20012012984 and 20012013002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20012013011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93513973 + ... + 93514186.

It is an arithmetic number, because the mean of its divisors is an integer number (5049760320).

Almost surely, 2^20012013013 is an apocalyptic number.

It is an amenable number.

20012013013 is a deficient number, since it is larger than the sum of its proper divisors (187028267).

20012013013 is a wasteful number, since it uses less digits than its factorization.

20012013013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187028266.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 20012013013 its reverse (31031021002), we get a palindrome (51043034015).

The spelling of 20012013013 in words is "twenty billion, twelve million, thirteen thousand, thirteen".