Base | Representation |
---|---|
bin | 10111110110110… |
… | …01011110111011 |
3 | 111221120011101011 |
4 | 23323121132323 |
5 | 402212322001 |
6 | 31505134351 |
7 | 4646664652 |
oct | 1373313673 |
9 | 457504334 |
10 | 200120251 |
11 | a2a65341 |
12 | 5702a3b7 |
13 | 325c9c66 |
14 | 1c814199 |
15 | 1287ed51 |
hex | bed97bb |
200120251 has 2 divisors, whose sum is σ = 200120252. Its totient is φ = 200120250.
The previous prime is 200120203. The next prime is 200120257. The reversal of 200120251 is 152021002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200120251 - 215 = 200087483 is a prime.
It is a super-2 number, since 2×2001202512 = 80096229720606002, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200120257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060125 + 100060126.
It is an arithmetic number, because the mean of its divisors is an integer number (100060126).
Almost surely, 2200120251 is an apocalyptic number.
200120251 is a deficient number, since it is larger than the sum of its proper divisors (1).
200120251 is an equidigital number, since it uses as much as digits as its factorization.
200120251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 13.
The square root of 200120251 is about 14146.3864997391. The cubic root of 200120251 is about 584.9207295127.
Adding to 200120251 its reverse (152021002), we get a palindrome (352141253).
The spelling of 200120251 in words is "two hundred million, one hundred twenty thousand, two hundred fifty-one".
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