Base | Representation |
---|---|
bin | 1001000110011011011100… |
… | …00111001110011110101001 |
3 | 2121212010201122210012211201 |
4 | 10203031232013032132221 |
5 | 10110334240101121022 |
6 | 110321233135324201 |
7 | 4133553331343341 |
oct | 443155607163651 |
9 | 77763648705751 |
10 | 20012100020137 |
11 | 64160a1824285 |
12 | 22b258b980661 |
13 | b22196098274 |
14 | 4d283b273d21 |
15 | 24a8622b2127 |
hex | 12336e1ce7a9 |
20012100020137 has 2 divisors, whose sum is σ = 20012100020138. Its totient is φ = 20012100020136.
The previous prime is 20012100020093. The next prime is 20012100020161. The reversal of 20012100020137 is 73102000121002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11895732062361 + 8116367957776 = 3449019^2 + 2848924^2 .
It is a cyclic number.
It is not a de Polignac number, because 20012100020137 - 27 = 20012100020009 is a prime.
It is not a weakly prime, because it can be changed into another prime (20012100020177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006050010068 + 10006050010069.
It is an arithmetic number, because the mean of its divisors is an integer number (10006050010069).
Almost surely, 220012100020137 is an apocalyptic number.
It is an amenable number.
20012100020137 is a deficient number, since it is larger than the sum of its proper divisors (1).
20012100020137 is an equidigital number, since it uses as much as digits as its factorization.
20012100020137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 19.
Adding to 20012100020137 its reverse (73102000121002), we get a palindrome (93114100141139).
The spelling of 20012100020137 in words is "twenty trillion, twelve billion, one hundred million, twenty thousand, one hundred thirty-seven".
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