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200121153103147 is a prime number
BaseRepresentation
bin101101100000001001010110…
…001111100010010100101011
3222020120101200020120101012211
4231200021112033202110223
5202212241110143300042
61545342215532545551
760103163505563623
oct5540112617422453
9866511606511184
10200121153103147
11588459a4862981
121a5409a13222b7
13878846132a8b3
14375bcb616d883
1518209253ba017
hexb602563e252b

200121153103147 has 2 divisors, whose sum is σ = 200121153103148. Its totient is φ = 200121153103146.

The previous prime is 200121153103129. The next prime is 200121153103181. The reversal of 200121153103147 is 741301351121002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200121153103147 - 211 = 200121153101099 is a prime.

It is not a weakly prime, because it can be changed into another prime (200121153103127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060576551573 + 100060576551574.

It is an arithmetic number, because the mean of its divisors is an integer number (100060576551574).

Almost surely, 2200121153103147 is an apocalyptic number.

200121153103147 is a deficient number, since it is larger than the sum of its proper divisors (1).

200121153103147 is an equidigital number, since it uses as much as digits as its factorization.

200121153103147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 31.

The spelling of 200121153103147 in words is "two hundred trillion, one hundred twenty-one billion, one hundred fifty-three million, one hundred three thousand, one hundred forty-seven".