Base | Representation |
---|---|
bin | 101101100000001001010110… |
… | …001111100010010100101011 |
3 | 222020120101200020120101012211 |
4 | 231200021112033202110223 |
5 | 202212241110143300042 |
6 | 1545342215532545551 |
7 | 60103163505563623 |
oct | 5540112617422453 |
9 | 866511606511184 |
10 | 200121153103147 |
11 | 588459a4862981 |
12 | 1a5409a13222b7 |
13 | 878846132a8b3 |
14 | 375bcb616d883 |
15 | 18209253ba017 |
hex | b602563e252b |
200121153103147 has 2 divisors, whose sum is σ = 200121153103148. Its totient is φ = 200121153103146.
The previous prime is 200121153103129. The next prime is 200121153103181. The reversal of 200121153103147 is 741301351121002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200121153103147 - 211 = 200121153101099 is a prime.
It is not a weakly prime, because it can be changed into another prime (200121153103127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060576551573 + 100060576551574.
It is an arithmetic number, because the mean of its divisors is an integer number (100060576551574).
Almost surely, 2200121153103147 is an apocalyptic number.
200121153103147 is a deficient number, since it is larger than the sum of its proper divisors (1).
200121153103147 is an equidigital number, since it uses as much as digits as its factorization.
200121153103147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 31.
The spelling of 200121153103147 in words is "two hundred trillion, one hundred twenty-one billion, one hundred fifty-three million, one hundred three thousand, one hundred forty-seven".
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