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2001221101983 = 3667073700661
BaseRepresentation
bin11101000111110010000…
…100101010100110011111
321002022111112120020222110
4131013302010222212133
5230242000100230413
64131203121245103
7264404060462115
oct35076204524637
97068445506873
102001221101983
1170179315a884
12283a24a93793
1311693953671c
146cc06b13ab5
15370ca2d58c3
hex1d1f212a99f

2001221101983 has 4 divisors (see below), whose sum is σ = 2668294802648. Its totient is φ = 1334147401320.

The previous prime is 2001221101949. The next prime is 2001221101987. The reversal of 2001221101983 is 3891011221002.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-2001221101983 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2001221101983.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2001221101987) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333536850328 + ... + 333536850333.

It is an arithmetic number, because the mean of its divisors is an integer number (667073700662).

Almost surely, 22001221101983 is an apocalyptic number.

2001221101983 is a deficient number, since it is larger than the sum of its proper divisors (667073700665).

2001221101983 is an equidigital number, since it uses as much as digits as its factorization.

2001221101983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 667073700664.

The product of its (nonzero) digits is 1728, while the sum is 30.

Adding to 2001221101983 its reverse (3891011221002), we get a palindrome (5892232322985).

The spelling of 2001221101983 in words is "two trillion, one billion, two hundred twenty-one million, one hundred one thousand, nine hundred eighty-three".

Divisors: 1 3 667073700661 2001221101983