Base | Representation |
---|---|
bin | 11101000111110010000… |
… | …100101010100110011111 |
3 | 21002022111112120020222110 |
4 | 131013302010222212133 |
5 | 230242000100230413 |
6 | 4131203121245103 |
7 | 264404060462115 |
oct | 35076204524637 |
9 | 7068445506873 |
10 | 2001221101983 |
11 | 70179315a884 |
12 | 283a24a93793 |
13 | 11693953671c |
14 | 6cc06b13ab5 |
15 | 370ca2d58c3 |
hex | 1d1f212a99f |
2001221101983 has 4 divisors (see below), whose sum is σ = 2668294802648. Its totient is φ = 1334147401320.
The previous prime is 2001221101949. The next prime is 2001221101987. The reversal of 2001221101983 is 3891011221002.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-2001221101983 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2001221101983.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001221101987) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333536850328 + ... + 333536850333.
It is an arithmetic number, because the mean of its divisors is an integer number (667073700662).
Almost surely, 22001221101983 is an apocalyptic number.
2001221101983 is a deficient number, since it is larger than the sum of its proper divisors (667073700665).
2001221101983 is an equidigital number, since it uses as much as digits as its factorization.
2001221101983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 667073700664.
The product of its (nonzero) digits is 1728, while the sum is 30.
Adding to 2001221101983 its reverse (3891011221002), we get a palindrome (5892232322985).
The spelling of 2001221101983 in words is "two trillion, one billion, two hundred twenty-one million, one hundred one thousand, nine hundred eighty-three".
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