Base | Representation |
---|---|
bin | 111011101001000… |
… | …0100001100110001 |
3 | 12011110122201220211 |
4 | 1313102010030301 |
5 | 13044303140442 |
6 | 530325104121 |
7 | 100410061516 |
oct | 16722041461 |
9 | 5143581824 |
10 | 2001224497 |
11 | 937703648 |
12 | 47a258041 |
13 | 25b7b580c |
14 | 14dad730d |
15 | baa55617 |
hex | 77484331 |
2001224497 has 2 divisors, whose sum is σ = 2001224498. Its totient is φ = 2001224496.
The previous prime is 2001224483. The next prime is 2001224501. The reversal of 2001224497 is 7944221002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1390096656 + 611127841 = 37284^2 + 24721^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001224497 - 27 = 2001224369 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001224417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000612248 + 1000612249.
It is an arithmetic number, because the mean of its divisors is an integer number (1000612249).
Almost surely, 22001224497 is an apocalyptic number.
It is an amenable number.
2001224497 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001224497 is an equidigital number, since it uses as much as digits as its factorization.
2001224497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
The square root of 2001224497 is about 44735.0477478230. The cubic root of 2001224497 is about 1260.1781256949.
Adding to 2001224497 its reverse (7944221002), we get a palindrome (9945445499).
The spelling of 2001224497 in words is "two billion, one million, two hundred twenty-four thousand, four hundred ninety-seven".
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