Base | Representation |
---|---|
bin | 11101000111110010100… |
… | …110110011001001000001 |
3 | 21002022112011101212011012 |
4 | 131013302212303021001 |
5 | 230242004343043412 |
6 | 4131204041130305 |
7 | 264404226520163 |
oct | 35076246631101 |
9 | 7068464355135 |
10 | 2001230049857 |
11 | 701798211515 |
12 | 283a27a89995 |
13 | 11693b34a41c |
14 | 6cc07da2933 |
15 | 370caea1c22 |
hex | 1d1f29b3241 |
2001230049857 has 2 divisors, whose sum is σ = 2001230049858. Its totient is φ = 2001230049856.
The previous prime is 2001230049853. The next prime is 2001230049899. The reversal of 2001230049857 is 7589400321002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1546662835201 + 454567214656 = 1243649^2 + 674216^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001230049857 - 22 = 2001230049853 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001230049853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000615024928 + 1000615024929.
It is an arithmetic number, because the mean of its divisors is an integer number (1000615024929).
Almost surely, 22001230049857 is an apocalyptic number.
It is an amenable number.
2001230049857 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001230049857 is an equidigital number, since it uses as much as digits as its factorization.
2001230049857 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 41.
The spelling of 2001230049857 in words is "two trillion, one billion, two hundred thirty million, forty-nine thousand, eight hundred fifty-seven".
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