Base | Representation |
---|---|
bin | 11101000111110010101… |
… | …110101000011011101011 |
3 | 21002022112022021011201222 |
4 | 131013302232220123223 |
5 | 230242010404300042 |
6 | 4131204153132255 |
7 | 264404253131354 |
oct | 35076256503353 |
9 | 7068468234658 |
10 | 2001232103147 |
11 | 701799394152 |
12 | 283a286ba08b |
13 | 11693b8b8ba4 |
14 | 6cc08378d2b |
15 | 370cb25a2d2 |
hex | 1d1f2ba86eb |
2001232103147 has 2 divisors, whose sum is σ = 2001232103148. Its totient is φ = 2001232103146.
The previous prime is 2001232103047. The next prime is 2001232103219. The reversal of 2001232103147 is 7413012321002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001232103147 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001232103047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000616051573 + 1000616051574.
It is an arithmetic number, because the mean of its divisors is an integer number (1000616051574).
Almost surely, 22001232103147 is an apocalyptic number.
2001232103147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001232103147 is an equidigital number, since it uses as much as digits as its factorization.
2001232103147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 2001232103147 its reverse (7413012321002), we get a palindrome (9414244424149).
The spelling of 2001232103147 in words is "two trillion, one billion, two hundred thirty-two million, one hundred three thousand, one hundred forty-seven".
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