20013000043 has 2 divisors, whose sum is σ = 20013000044. Its totient is φ = 20013000042.

The previous prime is 20012999989. The next prime is 20013000047. The reversal of 20013000043 is 34000031002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20013000043 is a prime.

It is a super-3 number, since 3×20013000043³ (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 20012999987 and 20013000032.

It is not a weakly prime, because it can be changed into another prime (20013000047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006500021 + 10006500022.

It is an arithmetic number, because the mean of its divisors is an integer number (10006500022).

Almost surely, 2^20013000043 is an apocalyptic number.

20013000043 is a deficient number, since it is larger than the sum of its proper divisors (1).

20013000043 is an equidigital number, since it uses as much as digits as its factorization.

20013000043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 13.

Adding to 20013000043 its reverse (34000031002), we get a palindrome (54013031045).

The spelling of 20013000043 in words is "twenty billion, thirteen million, forty-three", and thus it is an aban number and an uban number.