Base | Representation |
---|---|
bin | 1001000110011101001110… |
… | …11010100110110111011011 |
3 | 2121212020012122210110221011 |
4 | 10203032213122212313123 |
5 | 10110343222204331300 |
6 | 110321512401154351 |
7 | 4133616214063210 |
oct | 443164732466733 |
9 | 77766178713834 |
10 | 20013061402075 |
11 | 6416545470805 |
12 | 22b27b992b9b7 |
13 | b222ba303911 |
14 | 4d28ccc0bb07 |
15 | 24a8bb8b5eba |
hex | 1233a76a6ddb |
20013061402075 has 24 divisors (see below), whose sum is σ = 28362625175808. Its totient is φ = 13722633317280.
The previous prime is 20013061402069. The next prime is 20013061402091. The reversal of 20013061402075 is 57020416031002.
It is not a de Polignac number, because 20013061402075 - 25 = 20013061402043 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1437234 + ... + 6487816.
It is an arithmetic number, because the mean of its divisors is an integer number (1181776048992).
Almost surely, 220013061402075 is an apocalyptic number.
20013061402075 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
20013061402075 is a deficient number, since it is larger than the sum of its proper divisors (8349563773733).
20013061402075 is a wasteful number, since it uses less digits than its factorization.
20013061402075 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5073243 (or 5073238 counting only the distinct ones).
The product of its (nonzero) digits is 10080, while the sum is 31.
Adding to 20013061402075 its reverse (57020416031002), we get a palindrome (77033477433077).
The spelling of 20013061402075 in words is "twenty trillion, thirteen billion, sixty-one million, four hundred two thousand, seventy-five".
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